[Cfp-interest] Quantum function

[James W Thomas]

Ok. Looks reasonable.
-Jim

On Jun 17, 2013, at 1:50 AM, Mike Cowlishaw <mfc at speleotrove.com> wrote:

> 
> As promised, I've checked 754.  The final sentence of 5.2 (Decimal exponent calculation) has:
> 
>    If x is infinite, Q(x) is +∞.
> 
> Therefore the result of quantum(x) where x is infinite should be  +∞  (not x).  This is consistent in that if x is finite the result is also not affected by the sign of x.
> 
> For when x is qNaN or sNaN I can think of no reason why the results would be different from any other single-argument  function or general operation.
> 
> Mike
> 

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