[Cfp-interest] Quantum function

[Mike Cowlishaw]

As promised, I've checked 754.  The final sentence of 5.2 (Decimal exponent
calculation) has:

   If x is infinite, Q(x) is +∞.

Therefore the result of quantum(x) where x is infinite should be  +∞  (not x).
This is consistent in that if x is finite the result is also not affected by the
sign of x.

For when x is qNaN or sNaN I can think of no reason why the results would be
different from any other single-argument  function or general operation.

Mike

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